Answer
B
Explain:I got it right definitely didn't search it up
but I promise it's right
Step-by-step explanation:
5m³ + 2m - 7m³ - 8m
= -2m³ -6m
= -2m(m² + 3)
Answer:
= 78
= 3.5
Step-by-step explanation:
First we need to find .
We can use the equation 
to solve for .
We can then change that equation to 
, since the Commutative Property of Addition says that you can have any addition in any order.
Now, we can solve the equation.
Now that we solved , we can now solve for .
Since 25 equals 
, we can solve the equation 
.
Here is how you solve it:
Since 
equals 3.5, which is the simplest form, that is the answer.
Hope this helps, and please mark me brainliest! :)
Answer:
$15,539.67
Step-by-step explanation:
Compound Interest Formula
where:
- A = final amount
- P = principal amount
- r = interest rate (in decimal form)
- n = number of times interest applied per time period
- t = number of time periods elapsed
Given:
- P = $11,000
- r = 5.8% = 0.058
- n = 4 (quarterly)
- t = 6 years
Substitute the given values into the formula and solve for A:
Therefore, the value of the investment after 6 years will be $15,539.67 to the nearest cent.
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
