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irinina [24]
3 years ago
12

What is the center and radius of the following circle: x^2 + (y – 6)^2 = 50

Mathematics
2 answers:
jeka943 years ago
6 0


<span>What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50, 
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find </span>(x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2), 
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2), 
svetoff [14.1K]3 years ago
5 0
Center: (0, 6)

radius = sqrt(50) = 5sqrt(2)
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