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Lelechka [254]
3 years ago
12

Find x value

%20%3D%200" id="TexFormula1" title=" {x}^{3} + {x}^{2} + 8x + 12 = 0" alt=" {x}^{3} + {x}^{2} + 8x + 12 = 0" align="absmiddle" class="latex-formula">
?? ​
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
<h2><em>step </em><em>-</em><em>1</em><em> </em></h2>

<em>Changes made to your input should not affect the solution:</em>

<em>Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". 1 more similar replacement(s).</em>

<em>x3+x2-8x-12 is not a perfect </em><em>cube</em>

<em>Factoring: x3+x2-8x-12 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)Group 2: (2x+3) • (-4)</em>

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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
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Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

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Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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Hey!

It says that it is the sum of 3 consecutive odd integers right?

So then we give these numbers some variables to work with like so...

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<u>x = 67</u><u />                     <u>x + 2 = 69</u><u />              <u /><u />   <u>x + 4 = 71
</u>
<u>
</u>


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When multiplying and dividing two numbers in scientific notation, why do u sometimes have to rewrite one factor ?
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You sometimes need to rewrite a factor because the lead number is not between 1 and 10 as it needs to be in scientific notation. For instance, if we had lead numbers of 2 and 5, as we do in the following problem.

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