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Lelechka [254]
3 years ago
12

Find x value

%20%3D%200" id="TexFormula1" title=" {x}^{3} + {x}^{2} + 8x + 12 = 0" alt=" {x}^{3} + {x}^{2} + 8x + 12 = 0" align="absmiddle" class="latex-formula">
?? ​
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
<h2><em>step </em><em>-</em><em>1</em><em> </em></h2>

<em>Changes made to your input should not affect the solution:</em>

<em>Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". 1 more similar replacement(s).</em>

<em>x3+x2-8x-12 is not a perfect </em><em>cube</em>

<em>Factoring: x3+x2-8x-12 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 </em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)</em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x3+x2 Group 2: -8x-12 Pull out from each group separately :Group 1: (x+1) • (x2)Group 2: (2x+3) • (-4)</em>

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I just need help. So, with this, since it’s 6.633 then would it just go back to 6.63 or to 6.60?
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