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jolli1 [7]
2 years ago
6

PLEASE HELP! Quick Math Question!!

Mathematics
1 answer:
valkas [14]2 years ago
3 0
20 boats = 800 fishes
1 boat = 800/20 = 40 fishes
6 boats = 40 × 6 = 240 fishes

Correct option A
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Factor the trinomial. Factor out the GCF first.<br> 5x^2y - 30xy^2 - 35y^3
anzhelika [568]

Answer: 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

The given expression: 5x^2y - 30xy^2 - 35y^3

It can be written as

5x^2y - (5\times6)x( y\times y) - (5\times7)(y^2\times y)

Taking out common factor  5y , we get

5y(x^2-6xy-7y^2)\\\\ =5y(x^2+xy-7xy-7y^2)\  \ [\because-6xy=xy-7xy]\\\\=5y(x(x+y)-7y(x+y))\\\\= 5y((x+y)(x-7y))\\\\=5y(x+y)(x-7y)

Hence, 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

3 0
3 years ago
Calculate the mean,median,and mode of the following set of data. Round to the nearest tenth 10,1,10,15,1,7,10,1,6,13
lions [1.4K]
Let's start with the mean. 

To find the mean of a data set, add all the numbers, then divide by the number of numbers there are. 

10 + 1 + 10 + 15 + 1 + 7 + 10 + 1 + 6 + 13 = 74
74/10 = 7.4

The mean is 7.4

Now for the median.

To find the median put all the numbers in order, then find the middle number.

1, 1, 1, 6, 7, 10, 10, 10, 13, 15

The number in between 7 and 10 is 8.5
The median is 8.5

And finally, the mode.

To find the mode, find the number that appears the most. 

1, 1, 1, 6, 7, 10, 10, 10, 13, 15

In this case, there are two modes. 1, and 10.

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
8 0
3 years ago
Read 2 more answers
True or false?
uysha [10]

Answer:

False: A function is a rule that assigns each vale of the independent variable to exactly one vale of the dependent variable.

Step-by-step explanation:

4 0
3 years ago
a relay team of 4 people runs 3 mile. it each person runs the same distance, how many miles does each person run?
Bingel [31]
Each person runs 3/4 miles.
6 0
2 years ago
Please helpppppp meeeee I neeeed answerssssssss
MissTica
I've done the first four questions. Use this method to answer the rest. For an odd number of objects find the cost of one and multiply by how many you are asked to find.

8 0
3 years ago
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