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abruzzese [7]
3 years ago
11

Answer the question I need help

Mathematics
2 answers:
Inessa05 [86]3 years ago
6 0

Answer:

the answer would be 38 :)

Step-by-step explanation:

24÷3=8

(8)+3+3 to the 3rd power

3×3×3=27

8+3=12 ->12+27=38

hopefully this helps :)

swat323 years ago
4 0

Answer:

Step-by-step explanation:

step 1: 24/3 which equals to 8.

Step 2: 8+3= 11

Step 3: 3*3*3=27

step four: 11+27=20 answer=38

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Please I really need help with this question
barxatty [35]

Answer:

Step-by-step explanation:

ABC and DEF are parallel lines. So, ∠ABE and ∠BED are co interior angles.

∠ABE + ∠BED = 180   {SUM OF CO INTERIOR ANGLE IS 180}

∠ABE+ 110.2 = 180

∠ABE = 180 - 110.2

∠ABE = 69.8

Now, ABC is straight line

∠ABE + ∠EBG + ∠CBG = 180

69.8 + ∠EBG + 34.8 = 180

104.6 + ∠EBG = 180

∠EBG = 180 - 104.6

∠EBG = 75.4

Again, DEF is straight line

∠DEB + ∠BEG + ∠GEF = 180

110.2 + ∠BEG + 25.6 = 180

∠BEG + 135.8 = 180

∠BEG = 180 - 135.8

∠BEG = 44.2

In triangle BEG,

∠BEG + x  + ∠EBG = 180  { sum of all angles of triangle is 180}

44.2 + x + 75.4 = 180

x + 119.6 = 180

x = 180 - 119.6

x = 60.4

3 0
3 years ago
Absolute value inequalities. 10-4|9y-10|<-94
Ivahew [28]

Answer: \begin{bmatrix}\mathrm{Solution:}\:&\:y4\:\\ \:\mathrm{Decimal:}&\:y4\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-\frac{16}{9}\right)\cup \left(4,\:\infty \:\right)\end{bmatrix}

Step-by-step explanation:

10-4\left|9y-10\right|

10-4\left|9y-10\right|-10

-4\left|9y-10\right|

\left(-4\left|9y-10\right|\right)\left(-1\right)>\left(-104\right)\left(-1\right)

4\left|9y-10\right|>104

\frac{4\left|9y-10\right|}{4}>\frac{104}{4}

\left|9y-10\right|>26

9y-1026

y4

5 0
3 years ago
1. Solve the equation. 2. Check your solution. k÷3=21
Sedaia [141]

Answer:

k = 63

Step-by-step explanation:

3 x 21 = 63

8 0
3 years ago
8-2x=5-4x<br> 4+3x=2-2x<br> 2(x-1)+2(3x-1)=0
vodka [1.7K]

Answer:

See the below part

Step-by-step explanation:

1)

8 - 2x = 5 - 4x

=> 8 - 5 = -4x + 2x

=> 3 = -2x

=> 3/-2 = x

=> -3/2 = x

2)

4 + 3x = 2 - 2x

=> 4 - 2 = -2x - 3x

=> -2 = -5x

=> 2 = 5x

=> 2/5 = x

3)

2(x - 1) + 2(3x - 1) = 0

=> 2x - 2 + 6x - 2 = 0

=> 8x - 4 = 0

=> 8x = 4

=> x = 4/8

=> x = 1/2

8 0
2 years ago
Read 2 more answers
HELP!!<br>Find the third term of (x^2+3y)^3
lana66690 [7]

Answer:

T_{3}=27{x}^{2}y^2

Step-by-step explanation:

The given binomial expression is:

( {x}^{2} + 3y)^{3}

When we compare to:

{(a +b)}^{n}

We have

a =  {x}^{2}

b = 3y \\ n = 3

The nth term is given by;

T_{r+1}=^nC_ra^{n-r}b^r

To find the 3rd term, we put:

r + 1 = 3 \\ r = 2

We substitute into the formula to get:

T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2

We simply:

T_{3}=3( {x}^{2} )^{1} \times 9y^2

T_{3}=27{x}^{2}y^2

3 0
3 years ago
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