Ask question

Ask question

All categories

4 years ago

14

Two beauticians, Lydia and Jackie, are working on your hair. Lydia can complete the work in 2 hours, while Jackie can complete t

he work in 1 hour. How many hours do the beauticians take if they work together?
A. one half
B.three halvess
C.two thirds
D.four thirds

2 answers:

4vir4ik [10]4 years ago

5 0

Answer:

Option C.

Step-by-step explanation:

Two beauticians Lydia and Jackie are working on your hair.

Lydia takes the time to complete the work = 2 hours

Per hour work done by Lydia = 1/2

Jackie complete the work = 1 hour

In one hour total work done by both Jackie and Lydia together = $1+\frac{1}{2}=1\frac{1}{2}or \frac{3}{2}$

therefore, time taken by both to complete the work will be = $\frac{1}{\frac{3}{2} }$ = $\frac{2}{3}$

Option C. two thirds is the correct option.

Pavlova-9 [17]4 years ago

4 0

That is not correct. I just took the test and the answer is 2/3

You might be interested in

Which circles have a circumference of 18pi units?

timurjin [86]

It's A and C, I've taken a test that has this question and it was correct when I answered this, so A and C is your answer.

3 0

3 years ago

KOUKLADINA HERE IS THE LIST OF BOTS>... I ALSO PUT THEM IN A MESSAGE TO YOU>>>>>>>>>>>>&g

Elodia [21]

Answer:

HUH WHAT DOES THIS MEAN?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The police use a speed gun to monitor one part of a highway. During one hour, 6 out of 25 cars were traveling above the speed li

Vlad [161]

<span>(6 / 25) X 100 = 24%</span>

4 0

3 years ago

Read 2 more answers

Help me with my algebra homework 1/4

Margaret [11]

Answer:

1) 24 2) $2 per pencil 3) 23 4) 15 5) $5 per eraser

6) 37 7) 16 8) $16

Step-by-step explanation:

hope this helps

5 0

3 years ago

Calculate the length of sides triangle pqr and determine weather or not triangle is a right angled. P(-4,6) q(6,1) r(2,9)

Tom [10]

$\bold{\huge{\underline{ Solution }}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

We have given the coordinates of the triangle PQR that is P(-4,6) , Q(6,1) and R(2,9)

<h3><u>To</u><u> </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>calculate </u><u>the </u><u>length </u><u>of </u><u>the </u><u>sides </u><u>of </u><u>given </u><u>triangle </u><u>and </u><u>also </u><u>we </u><u>have </u><u>to </u><u>determine </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u>

Coordinates of P =( x1 = -4 , y1 = 6)
Coordinates of Q = ( x2 = 6 , y2 = 1 )
Coordinates of R = ( x3 = 2 , y3 = 9 )

<u>By </u><u>using </u><u>distance </u><u>formula </u>

$\pink{\bigstar}\boxed{\sf{Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>

Length of side PQ

$\sf{ = }{\sf\sqrt{ (6 - (-4))^{2} + (1 - 6)^{2}}}$

$\sf{ = }{\sf\sqrt{ (6 + 4 )^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ (10)^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ 100 + 25 }}$

$\sf{ = }{\sf\sqrt{ 125 }}$

$\sf{ = 5 }{\sf\sqrt{ 5 }}$

Length of QR

$\sf{ = }{\sf\sqrt{(2 - 6)^{2} + (9 - 1)^{2}}}$

$\sf{ = }{\sf\sqrt{(- 4 )^{2} + (8)^{2}}}$

$\sf{ = }{\sf\sqrt{16 + 64 }}$

$\sf{ = }{\sf\sqrt{80 }}$

$\sf{ = 4 }{\sf\sqrt{5 }}$

Length of RP

$\sf{ = }{\sf\sqrt{ (-4 - 2 )^{2} + (6 - 9)^{2}}}$

$\sf{ = }{\sf\sqrt{ (-6 )^{2} + (-3)^{2}}}$

$\sf{ = }{\sf\sqrt{ 36 + 9 }}$

$\sf{ = }{\sf\sqrt{ 45 }}$

$\sf{ = 3}{\sf\sqrt{ 5 }}$

<h3><u>Now</u><u>, </u></h3>

We have to determine whether the triangle PQR is right angled triangle

<h3>Therefore, </h3>

<u>By </u><u>using </u><u>Pythagoras </u><u>theorem </u><u>:</u><u>-</u>

Pythagoras theorem states that the sum of squares of two sides that is sum of squares of 2 smaller sides of triangle is equal to the square of hypotenuse that is square of longest side of triangle

<u>That </u><u>is</u><u>, </u>

$\bold{ PQ^{2} + QR^{2} = PR^{2}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>,</u>

$\bold{ 125 + 80 = 45 }$

$\bold{ 205 = 45 }$

<u>From </u><u>above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The triangle PQR is not a right angled triangle because 205 ≠ 45 .

6 0

3 years ago