Which sequence is modeled by the graph below? (6 points)

Mathematics

1 answer:

vovangra [49]2 years ago

8 0

You haven’t put a picture of the graph

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I’m confused about #6, anyone know the answer?

natita [175]

Answer:

Step-by-step explanation:

Because B and D were both according to the Mean, and that is the same in the table so we can cross those out. And C is wrong because there are not less of a variation but more variation. So A would be your answer!

Hope this helps!

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2 years ago

PLS ANSWER! Which movie has more consistent ages?

Alex

Answer:

I think B

Step-by-step explanation:

because their age group is 20-25 more of a constant age group

compared to 20-30

6 0

2 years ago

A model for the population in a small community after t years is given by P(t)=P0e^kt.

LUCKY_DIMON [66]

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}$

a)

so, if the population doubled in 5 years, that means t = 5. So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
I=\textit{initial amount}\to &1\\
r=rate\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r
\\\\\\
\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\
\textit{how long to tripling?}\quad 
\begin{cases}
A=3\\
I=1
\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}$

$\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t
\\\\\\
\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t$

b)

A = 10,000, t = 3

$\bf \begin{cases}
A=10000\\
t=3
\end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I
\\\\\\
6597.53955 \approx I$

3 0

3 years ago

Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 po

Nesterboy [21]

<span>First, the formula would be like this dP / dt= KP.
Secondly, since dP is given which is 6.9. Substitute it from the equation.

P(0) = 6.9 x 10^6
integral 1 divided by pdp which will look like this,

integral 1/ PdP = integral kdt

the answer would be .0019 or
k=.0019</span>

6 0

3 years ago

Read 2 more answers

HELP DUE TODAY! WILL GIVE 18 PTS!!<br><br> * Question is in picuture *

gulaghasi [49]

Answer:

7/8

Step-by-step explanation:

you find the common denominator which is 2 so you can divide both by two to get 7/8

6 0

2 years ago