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3 years ago

HELLLLPPPPP 50 PTS to whoever answers!!!!! Due in 1 hr

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

Some relationships:

Angle FGH + Angle FHG = 90

sin(FGH) = cos(FHG)

cos(FGH) = sin(FHG)

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Find the slope of the line passing through the points (-3,7) AND (2,-6)

castortr0y [4]

-13/5. The equation to find the slope between 2 points is y sub 2-y sub 1/x sub 2-x sub 1. Or in this case, -6-7/2+3. -6-7=-13, 2+3=5. So the slope is -13/5.

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3 years ago

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A survey asks 48 randomly chosen students if they plan to buy a school newspaper this week. Of the 48 surveyed,32 plant to buy a

spayn [35]

The answer is 540 because 32/48 is 2/3 and 360/540 equals 2/3

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3 years ago

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

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3 years ago

Does anyone know how to solve this??

sergij07 [2.7K]

Volume of a cone = (1/3) x Area of the base (B) x height(h)
V = (1/3)·420·180
= 25200 mm³

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3 years ago

A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t

Andre45 [30]

Answer: Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

Step-by-step explanation:

Given: Width of pencil box = $5\dfrac14\text{ inches}=\dfrac{21}{4}\text{ inches}$

Width of seven pencils = $2\dfrac58\text{ inches}=\dfrac{16+5}{8}\text{ inches}=\dfrac{21}{8}\text{ inches}$

Width of box is not taken up by pencils = Width of pencil box - Width of seven pencils

$\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}$

Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil = (Width of seven pencils ) ÷ 7

$=\dfrac{21}{8}\div7\\\\=\dfrac{21}{8}\times\dfrac17\\\\=\dfrac38\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

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2 years ago

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