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Pavlova-9 [17]
3 years ago
5

Find the slope glencoe algebra pg 175-176 textbook answers

Mathematics
1 answer:
prisoha [69]3 years ago
8 0
I would love to answer if you tell me what book
You might be interested in
How can I find x? Click for picture.
romanna [79]
Answer:   You add up all the terms given of EACH angle, and make this an addition problem that is "equal to 180" ; since all triangles have three angles that add up to 180 degrees.  Then you solve for "x".
__________________________________________________
(as follows) ;  to get:    " x = 29 ⅔ ° " .
_______________________________________

         3x + 4 + 2x + x + 8 = 180  ;
_______________________________________
Combine the "like terms" ;

         3x + 2x + x = 6x ;

                 4 + 8 = 12

So, we have:  6x + 12 = 180 ;

Now, subtract "12" from each side of the equation:
__________________________________________
  6x + 12 − 12 = 180 <span>− 12 ;
</span>__________________________________________
 to get: 

      6x = 178 ;

Now, divide EACH SIDE of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ;
______________________________________
    6x / 6 = 178 / 6 ;

to get:  x = 178/6 = 29 ⅔ ° .
______________________________________
             x = 29 ⅔ ° .
______________________________________
6 0
4 years ago
A two-digit number is written at random. The probability that the number will be odd is . The probability that the number will b
Makovka662 [10]
Step-by-step explanation:
GIVEN: Two digit number means we will have to choose from numbers 0-9 for the second digit and 1-9 for the first digit. (since zero can't be in the tens place)
Formula: We will use m x n. That is, m is the number of elements we can use for the first digit and n will be the number of elements we can use for the second digit.
Sample Space: To get the probability, we must find the sample space or all the outcomes.
m - 9 elements (1-9)
m - 9 elements (1-9)n - 10 elements (0-9)
m x n = 9x10 =90
90 is our sample space.
A. An odd number
Conditions: For an odd number, the second number will determine whether or not it is an odd number. For the first digit, we can use 1-9.
Elements:
m - 9 elements (1-9)
m - 9 elements (1-9)n - 5 elements (1,3,5,7,9)
m x n=9x5=45
SOLVE (probability)
Probability= possible outcomes/sample space
P=45/90
P=1/2
B. Larger than 75.
Conditions: The first digit could be equal to 7 or greater. But n will only be greater than 5 if and only if m=7 and n could be any number if m>7.
Elements 1:
m - 1 element (7)
m - 1 element (7)n - 4 elements (6,7,8,9)
m - 1 element (7)n - 4 elements (6,7,8,9)m x n=1x4=4
Elements 2:
m - 2 elements (8,9)
m - 2 elements (8,9)n - 10 elements (0,1,2,3,4,5,6,7,8,9,)
m - 2 elements (8,9)n - 10 elements (0,1,2,3,4,5,6,7,8,9,)mxn=2x10=20
TOTAL: 4+20=24
SOLVE (PROBABILITY)
Probability= possible outcomes/sample space
P=24/90
P=4/15
C. multiple of 5
Condition: the second digit must be either 0 or 5 and the first digit could be any digit.
Elements:
m - 9 elements (1-9)
m - 9 elements (1-9)n - 2 elements (0,5)
m x n =9x2=18
SOLVE (PROBABILITY)
P=18/90
P=1/5
D. An even number smaller than 40
Condition: The first digit could be equal to 4 but the second digit must be even (excluding zero). Another situation is the first digit would be greater than 4 and the second digit would be any even number.
Elements 1:
m - 1 element (4)
n - 4 elements (2,4,6,8)
m x n = 1x4=4
Elements 2:
m - 5 elements (5,6,7,8,9)
n - 5 elements (0,2,4,6,8)
mxn=5x5=25
TOTAL: 25+4=29
SOLVE: Probability
P=29/90
6 0
3 years ago
Round 961 to one significant figure
oksano4ka [1.4K]
1000 because i rounded the hundreth's to get one significant figure, and anything more than 5 is rounded up, anything less than 5 is rounded down.


Hope i did some use! <3
7 0
3 years ago
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than  the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

5 0
4 years ago
You are dealth one card from a 52-card deck. find the probability that you are dealt a two or a black card
grigory [225]
The probability of getting a 2 or a getting a black card, find individual probabilities; 

A standard deck has 52 cards. 

There are 4 2's in a normal deck; probability of getting it is 4/25 

The probability of getting a black card is; 26/52 since half the deck is red and black. 

Now add up the probabilities since it says "or" 

(4/52)+(26/52)=30/52 probability of the card that you were dealt being a two or a black card. 

Hope I helped :) 
6 0
3 years ago
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