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HACTEHA [7]
3 years ago
12

In the number 956,783,529 how does the value of the digit 5 in the ten millions place compare to the 5 in the hundreds place

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
The 5 in the ten millions place is 100,000 times greater than the 5 in the hundreds place
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Calculate the value of 18(-3)
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1. Two students went to McDonald's. They each bought the same snack, which included a shake
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6 0
3 years ago
2/3x + 1/6 = -3/4x + 1
kupik [55]
\frac{2}{3} x +  \frac{1}{6}  =  -\frac{3}{4} x + 1

First, simplify \frac{2}{3} x to \frac{2x}{3} / Your problem should look like: \frac{2x}{3} +  \frac{1}{6} =  -\frac{3}{4} x + 1
Second, simplify \frac{3}{4} x to \frac{3x}{4} / Your problem should look like: \frac{2x}{3} +  \frac{1}{6} =  -\frac{3x}{4} + 1
Third, multiply both sides by 12 (the LCM of 3 and 4) / Your problem should look like: 8x + 2 = -9x + 12
Fourth, subtract 2 from both sides. / Your problem should look like: 8x = -9x + 12 - 2
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Sixth, add 9x to both sides. / Your problem should look like: 8x + 9x = 10
Seventh, add 8x + 9x to get 17x. / Your problem should look like: 17x = 10
Eighth, divide both sides by 17. / Your problem should look like: x =  \frac{10}{17}

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7 0
3 years ago
Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides? It would be a great he
bija089 [108]

Answer: AC= 10 cm and CE= 5 cm


Step-by-step explanation:

In the given picture, Δ ADE is a right triangle

∴ By Pythagoras theorem,

AD^2+DE^2=AE^2\\\Rightarrow\ (8+4)^2+9^2=AE^2\\\Rightarrow\ AE^2=12^2+9^2\\\Rightarrow\ AE^2=144+81=225\\\Rightarrow\ AE=15\ cm

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

\frac{AB}{AC}=\frac{AD}{AE}\\\Rightarrow\frac{8}{AC}=\frac{12}{15}\\\Rightarrow\ AC=\frac{8\times15}{12}\\\Rightarrow\ AC=10\ cm

Now, AE=AC+CE

⇒CE=AE-AC

⇒CE=15-10=5 cm


4 0
3 years ago
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