Answer:
This may not be the numbers but just follow the way in how i did it hope it helps!!!
Step-by-step explanation:
SA= 2lw x 2lh x 2wh
Length - 5m
Width - 4m
Height - 6m
= 2 (5 x 4)+2 (5 x 6)+2 (4 x 6)
=2 ( 20)+2 (30)+2 (24)
= 40 + 60 + 48
=148
The dimensions of a second rectangular prism that will have the same surface area will be the below:
Length - 6m
Width - 5m
Height - 4m
SA = 2lw + 2lh + 2wh
= 2(6 x 5)+2 ( 6 x 4) +2 ( 5 x 4)
=2(30)+2 (24)+2 (20)
=60 + 48 + 40
= 148
Part A).
If 100 fish all had the same weight, and they weighed
235 pounds when they were all on the scale at the
same time, then each fish weighed
235 / 100 pounds .
Part-B).
You can find that actual weight with your calculator.
235 / 100 = 2.35 pounds .
Part-C).
If there were only 10 fish but their total weight was still 235 pounds,
then each fish would have to weigh a lot more, to make up the same
weight with only 10 of them.
Now, each fish would have to weigh 235 / 10 pounds .
That number is 235/10 = 23.5 pounds.
If there were only 1/10 as many fish, then in order to add up to the
same total weight, each fish would have to be 10 times as heavy.
This problem can be solved by making use of the Cosine Law. In general form, it is:
b2 = a2 + c2 - 2ac cos B
The given values are:
a = 8.75 cm
c = 4.26 cm
B = 87<span>°
Plugging in the values:
b2 = 8.75^2 + 4.26^2 - 2(8.75)(4.26) cos 87
b = 9.53 cm
So, the answer is:</span>
C. 9.53 centimeters
