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Answer:
deleting Internet browsing history.
Step-by-step explanation:
Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A
Artyom0805 [142]
Answer:
(i) U' = Φ
(ii) A∩A' = Φ
(iii) A – ( B U C) = {5,7,9}
(iv) A' U ( B U C ) = {2,4,6,8,10}
(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}
Step-by-step explanation:
Making assumptions about where parentheses should be,
<span>Let u = -7x </span>
<span>du = -7dx </span>
<span>dv = e^(2x) dx </span>
<span>v = e^(2x)/2 </span>
<span>∫ -7xe^(2x) dx = </span>
<span>-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = </span>
<span>-7xe^(2x)/2 + 7e^(2x)/4 + c</span>
