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solmaris [256]
3 years ago
14

Pwease help fast this is mah last question!

Mathematics
1 answer:
inessss [21]3 years ago
8 0

Answer:

A  = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB  (Call this point E).  Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units.  Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

       (21 + 16) units

A  = --------------------- * (12 units),   which simplifies to:

                  2

A = (37/2 units)(12 units)  =  A  = 37*6 units  =  A  = 222 units^2

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