Answer:
20
Step-by-step explanation:
This is a binomial distribution
n = 100; p = 1/5
E(x) = np = (100)(1/5) = 20
Notice that
13 - 9 = 4
17 - 13 = 4
so it's likely that each pair of consecutive terms in the sum differ by 4. This means the last term, 149, is equal to 9 plus some multiple of 4 :
149 = 9 + 4k
140 = 4k
k = 140/4
k = 35
This tells you there are 35 + 1 = 36 terms in the sum (since the first term is 9 plus 0 times 4, and the last term is 9 plus 35 times 4). Among the given options, only the first choice contains the same amount of terms.
Put another way, we have

but if we make the sum start at k = 1, we need to replace every instance of k with k - 1, and accordingly adjust the upper limit in the sum.


Answer:
62.5%
Step-by-step explanation:
To find percentage of win, we simply need to find the number of games won and divide it by the total number of games played. Then we will multiply that answer by 100 (to get percentage).
So,
Number of games won = 15
Total number of games = 15 + 9 = 24
Percentage of Win = 
Answer is 62.5%
Radian: is the standard unit of angular measure, used in many areas of mathmatics.
degree: is a measuement of plane angle, defined by representing a full rotation as 360 degrees.
Both are two units for measuring angles. There are at least four such units, but degrees and radians are most likely to encounter high school and college.