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Salsk061 [2.6K]
3 years ago
13

16. WILL MARK BRAINLIEST!! HELP! ​

Mathematics
1 answer:
Komok [63]3 years ago
8 0

Step-by-step explanation:

\frac{3}{2x + 5}  +  \frac{5}{x - 5}  \\  \\  =  \frac{3(x - 5) + 5(2x + 5)}{(2x + 5)(x - 5)} \\  \\  =  \frac{3x - 15 + 10x + 25}{(2x + 5)(x - 5)} \\  \\  =  \frac{3x + 10x + 25- 15 }{2 {x}^{2} - 10x + 5x - 25 }  \\  \\   =  \frac{13x  + 10 }{2 {x}^{2} - 5x - 25 }  \\  \\

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Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all
DanielleElmas [232]

find y=mx+b for line parallel to AB.

The line that is parallel will have the same slope as line AB:

the slope of line AB is

m=(8-3)/(-10-2)

=5/-12

=-5/12

Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).

at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.

To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so

4+4=8

7 0
2 years ago
What goes into 125 and 560 evenly
nikitadnepr [17]
The only numbers that go into 125 and 560 evenly are 1 and 5
8 0
3 years ago
(PLEASE ANSWER + BRAINLIEST ANSWER!!)
murzikaleks [220]

The arc length, radius and the included angle are related as

r\theta=\widehat {XYZ} where \theta is in radians.

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Correct choice is (B).

8 0
3 years ago
Read 2 more answers
Jodi bought a new sofa for $1,430, including finance charge. She made down payment of $130 and paid off the balance in 18 months
m_a_m_a [10]
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6 0
2 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
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