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3 years ago

Evaluate a + b for a = 43 and b = -29. HELP ME I ONLY HAVE 1 hourrr

Mathematics

2 answers:

iren [92.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

a + b = 43 +(-29) =43-29 = 14

worty [1.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

Substitute the given values for a and b into the expression and evaluate

a + b = 43 + (- 29) = 43 - 29 = 14

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Solve −4(x + 10) − 6 = −3(x − 2). (1 point)

AURORKA [14]

Hey there!!

Given equation :

... -4 ( x + 10 ) - 6 = -3 ( x - 2 )

Using the distributive property :

... -4x - 40 - 6 = -3x + 6

Combining like terms :

... -4x - 46 = -3x + 6

Adding 46 on both sides :

... -4x = -3x + 52

Adding 3x on both sides :

... -x = 52

... x = -52

Hope helps!

8 0

3 years ago

39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$

4 0

2 years ago

6 divided by 1 5/16

kkurt [141]

1 7/8 is the answer

Please mark brainiest

3 0

2 years ago

Read 2 more answers

In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile.

elixir [45]

Answer:

Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232

Step-by-step explanation:

Total number of students = 10 students.

Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

To find the mean, at first we have to take the sum of all given data and then divide with the number of students.

Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2

Mean = 31.2 / 10 = 3.12

$\text{Standard deviation, S} = \sqrt{\frac{\sum x^{2} - \left [ (\sum x)^{2}/n \right ]}{n-1}} \\S = 1.8232 \\\rm The \ Variance = S^{2} = 3.324$

5 0

3 years ago

Suppose there are 310 first-year lawyers in a particular metropolitan area with an average starting salary of $156,000 and a sta

vlada-n [284]

Answer:

$ 2263

Step-by-step explanation:

In this case to calculate the standard error of the mean, we only need the standard deviation (sd) and the number of the random sample (n).

sd = 13000

n = 33

SE = sd / (n ^ (1/2))

replacing:

SE = 13000 / (33 ^ (1/2))

SE = 2263.01

What the standard error of the mean for a random sample of 33 first-year lawyers means is $ 2263

6 0

3 years ago