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finlep [7]
2 years ago
11

A line with a slope of 5 passes through the point (2, 5). What is its equation in

Mathematics
2 answers:
Olenka [21]2 years ago
7 0

Answer:

<h2>         y = 5x - 5</h2>

Step-by-step explanation:

slope-intercept form of equation:  y = mx + b

where m is slope and b is y-intercept

If line y=ax+b passes through point (x₀,y₀) that means

that the equation y₀=ax₀+b is true

(2, 5)    ⇒   x=2,   y=5

m = 5

So:

              5 = 5×2 + b

               5 = 10 + b

               b = -5

Therefore equation in  slope-intercept form:

                                                                      y = 5x + (-5)

                                                                      y = 5x - 5                          

Maru [420]2 years ago
6 0

Answer: y = 5x - 5

Step-by-step explanation:

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Paraphin [41]

Given:

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One angle is 85°.

To find:

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Solution:

∠2 and 85° are vertically opposite angles and ∠1 and ∠3 are vertically opposite angles.

Vertical angle theorem:

If two lines are intersecting, then the vertically opposite angles are congruent.

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Sum of the adjacent angles in a straight line = 180°

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Subtract 85° from both sides.

85° + m∠3 - 85° = 180° - 85°

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By vertical angle theorem:

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3 years ago
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andre [41]
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