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finlep [7]
3 years ago
11

A line with a slope of 5 passes through the point (2, 5). What is its equation in

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

<h2>         y = 5x - 5</h2>

Step-by-step explanation:

slope-intercept form of equation:  y = mx + b

where m is slope and b is y-intercept

If line y=ax+b passes through point (x₀,y₀) that means

that the equation y₀=ax₀+b is true

(2, 5)    ⇒   x=2,   y=5

m = 5

So:

              5 = 5×2 + b

               5 = 10 + b

               b = -5

Therefore equation in  slope-intercept form:

                                                                      y = 5x + (-5)

                                                                      y = 5x - 5                          

Maru [420]3 years ago
6 0

Answer: y = 5x - 5

Step-by-step explanation:

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9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
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Answer:

63.5

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x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

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