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Helga [31]
3 years ago
11

Ron is creating building blocks in Word. How can he make the building blocks that he created available?

Computers and Technology
2 answers:
daser333 [38]3 years ago
7 0

A) Store those building in Normal template

Sergio039 [100]3 years ago
6 0

Answer:

The correct answer is  A) Store those buildings in the Normal template.

Explanation:

Word usually stores the building blocks in a file template. So, with the purpose of modifying or making the building blocks available, it is strictly necessary to save the document as a normal template.

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This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
aleksandr82 [10.1K]

Answer:

Question Options :

(1) Prompt the user to input five pairs of numbers: A player’s jersey number (0 – 99) and the player’s rating (1 – 9). Store the jersey numbers in one int array and the ratings in another int array. Output these array(i.e., output the roster).

(2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. The program initially outputs the menu, and outputs the menu after a user chooses an option. The program ends when the user chooses the option to Quit. For this step, the other options do nothing. (2 pt)

(3) Implement the “Output roster” menu option. (1 pt)

(4) Implement the “Add player” menu option. Prompt the user for a new player’s jersey number and rating. Append the values to the two arrays. (1 pt)

(5) Implement the “Delete player” menu option. Prompt the user for a player’s jersey number. Remove the player from the roster (delete the jersey number and rating). (2 pts)

(6) Implement the “Update player rating” menu option. Prompt the user for a player’s jersey number. Prompt again for a new rating for the player, and then change that player’s rating. (1 pt)

(7) Implement the “Output players above a rating” menu option. Prompt the user for a rating. Print the jersey number and rating for all players with ratings above the entered value. (2 pts)

/******************************************************************************

This program will store roster and rating information for a soccer team.

                             

*******************************************************************************/

#include <iostream>

#include <vector>

using namespace std;

int main() {

   vector< int> jerseyNumber;

   vector< int> rating;

   int temp;

   for (int i = 1; i <= 5; i++) {

       cout << "\nEnter player " << i << "'s jersey number: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 99)){

           jerseyNumber.push_back(temp);}

       cout << "Enter player " << i << "'s rating: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 9)){

       rating.push_back(temp);}

       cout << endl;

   } cout << endl;

   cout << "ROSTER" << endl;

   for (int i = 0; i < 5; i++)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i) << ", Rating: " << rating.at(i) << endl;

   char option;

   while (true) {

       cout << endl;

       cout << "MENU" << endl;

       cout << "a - Add player" << endl;

       cout << "d - Remove player" << endl;

       cout << "u - Update player rating" << endl;

       cout << "r - Output players above a rating" << endl;

       cout << "o - Output roster" << endl;

       cout << "q - Quit" << endl << endl;

       cout << "Choose an option: " << endl;

       cin >> option;

       switch (option) {

           case 'a':

           case 'A':

               cout << "Enter another player's jersey number: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 99)){

                   jerseyNumber.push_back(temp);}

               cout << "Enter another player's rating: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 9)){

                   rating.push_back(temp);}

               break;

           case 'd':

           case 'D':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       jerseyNumber.erase(jerseyNumber.begin() + i);

                       rating.erase(rating.begin() + i);

                       break; }

               } break;

           case 'u':

           case 'U':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       cout << "Enter a new rating " << "for player: ";

                       cin >> temp;

                       rating.at(i) = temp;

                       break; }

               } break;

           case 'r':

           case 'R':

               cout << "Enter a rating: ";

               cin >> temp;

               cout << "\nABOVE " << temp << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

                   if (rating.at(i) > temp)

               cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

               << ", Rating: " << rating.at(i) << endl;

               break;

           case 'o':

           case 'O':

               cout << "ROSTER" << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

               cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

               << ", Rating: " << rating.at(i) << endl;

               break;

           case 'q':

               return 0;

               default: cout << "Invalid menu option." << " Try again." << endl;

       }

     }

   }

Explanation:

6 0
3 years ago
Each TextField has a text property that's returned by its textProperty method as a StringProperty. The StringProperty method ___
masha68 [24]

Answer:

B: Bind

Explanation:

JavaFX property binding permits the synchronization of the value of two properties in such a way that whenever there is a change in one of the properties, there is an immediate update on the value of the other property. In this way, The StringProperty method bind receives an ObservableValue as an argument. When the ObservableValue changes, the bound property is updated accordingly.

4 0
3 years ago
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