![\huge \boxed{\mathbb{QUESTION} \downarrow}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cboxed%7B%5Cmathbb%7BQUESTION%7D%20%5Cdownarrow%7D)
![\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cboxed%7B%5Cmathfrak%7BAnswer%20%5C%3A%20with%20%5C%3A%20Explanation%7D%20%5Cdownarrow%7D)
To solve this equation, at first, let's just substitute x with 2.
So, the equation becomes ⇨ 2+4/3×2
![\tt \: \frac{x + 4}{3x} \\ \\ \tt \:\dashrightarrow \frac{(2) + 4}{3(2)} \\ \\ \tt \: Add \: 2 \: and \: 4 \: to \: get \: 6. \\ \\ \tt \: = \frac{6}{3\times 2} \\ \\ \tt \:Multiply \: 3 \: and \: 2 \: to \: get \: 6. \\ \\ \tt \:= \frac{6}{6} \\ \\\tt \: Divide \: 6 \: by \: 6 \: to \: get \: 1. \\ \\ = \boxed{ \boxed{ \bf \: 1}}](https://tex.z-dn.net/?f=%20%20%5Ctt%20%5C%3A%20%5Cfrac%7Bx%20%2B%204%7D%7B3x%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctt%20%5C%3A%5Cdashrightarrow%20%5Cfrac%7B%282%29%20%2B%204%7D%7B3%282%29%7D%20%20%5C%5C%20%20%5C%5C%20%5Ctt%20%5C%3A%20Add%20%5C%3A%20%202%20%20%5C%3A%20and%20%20%5C%3A%204%20%20%5C%3A%20to%20%20%5C%3A%20get%20%20%5C%3A%206.%20%5C%5C%20%20%5C%5C%20%5Ctt%20%5C%3A%20%3D%20%5Cfrac%7B6%7D%7B3%5Ctimes%202%7D%20%20%5C%5C%20%20%5C%5C%20%5Ctt%20%5C%3AMultiply%20%20%5C%3A%203%20%20%5C%3A%20and%20%5C%3A%20%202%20%20%5C%3A%20to%20%20%5C%3A%20get%20%5C%3A%20%206.%20%5C%5C%20%20%5C%5C%20%20%5Ctt%20%5C%3A%3D%20%20%5Cfrac%7B6%7D%7B6%7D%20%20%5C%5C%20%20%5C%5C%5Ctt%20%5C%3A%20Divide%20%5C%3A%20%206%20%5C%3A%20%20by%20%20%5C%3A%206%20%5C%3A%20%20to%20%5C%3A%20%20get%20%5C%3A%20%201.%20%5C%5C%20%20%5C%5C%20%20%3D%20%5Cboxed%7B%20%5Cboxed%7B%20%5Cbf%20%5C%3A%20%201%7D%7D)
Answer:
8
Explanation:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx – 11 = -9
To solve algebraically, try to get cotx alone.
First, add 11 to both sides:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx – 11
+ 11 = -9
+ 11![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx = 2
Now divide by
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
on both sides, which is the same as multiplying the other side by 4:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx ÷
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
= 2 ÷
cotx = 8
You can make an inequality out of this: 20≥2x+10
Answer:
Step-by-step explanation:
1/3+1/5×1/9 = 1/3+1/45 = 9/45+1/45 = 10/45 = 2/9
The easiest way would be to subtract 112 from 158 to get 46 that is the difference. Then divide by 2 to find the speed of wind, in this case that would be 23. So the wind speed was 23 km/h and to get the plane speed add or subtract 23 from the sped of the plane (112+23 or 158-23) to get 135 km/h so the plane moved at 135 km/h while the wind speed was 23 km/h