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vlada-n [284]
3 years ago
12

Two shorter sides of a triangle are the same length. The length of the longer side is 5 m longer than each of the shorter sides.

The perimeter of the triangle is 29 m.
Please Help!!
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
Represent the shorter sides as  x and the longer side as x + 5You know the Perimeter has to equal the sum of all three sides which is 29.So the equation to solve for x is 29 = x + x + (x + 5)
Each x is a shorter side and the 5+x is the long side. so then just solve for x.29 = 3x + 5 subtract 5 from each side29 - 5 = 3x24 = 3x then divide each side by 324/3 = x8 = x x equals 8 so each short side is 8m long. to get the length of the long side add 5+8=13m 
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Answer:

a) Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

b) t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5    

The degrees of freedom are given by:

df=n-1=49-1=48  

The p value is given by:

p_v =P(t_{(48)}  

c) 7359-2.01\frac{840}{\sqrt{49}}=7117.8    

7359+2.01\frac{840}{\sqrt{49}}=7600.2    

d) For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

Step-by-step explanation:

Part a and b

Data given

\bar X=7359 represent the sample mean

\sigma=840 represent the population standard deviation

n=49 sample size  

\mu_o =7539 represent the value to test

t would represent the statistic  

p_v represent the p value

Hypothesis to verify

We want to verify if the mean life is different from 7539 hours, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7539  

Alternative hypothesis:\mu < 7539  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5    

The degrees of freedom are given by:

df=n-1=49-1=48  

The p value is given by:

p_v =P(t_{(48)}  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

Part c

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We can find the critical value using the confidence level given of 95% and using the t distribution with 48 degrees of freedom we got t_{\alpha/2}=\pm 2.01

Now we have everything in order to replace into formula (1):

7359-2.01\frac{840}{\sqrt{49}}=7117.8    

7359+2.01\frac{840}{\sqrt{49}}=7600.2    

Part d

For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

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