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2 years ago

To decorate a cake you make a shade of purple icing using 2 drops of red food coloring for every 3 drops of blue

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

8 0

Answer:

Step-by-step explanation: 38 because multiply 12 by 3 and add 2

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Josiah want to gp to the movies with his friends. Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purcha

ss7ja [257]

Answer:

The equation that represents the number of tickets that Josiah can buy with $45.50

3 + 8.50x = 45.50

The number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

Step-by-step explanation:

Let the number of tickets be represented by x

Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purchasing the tickets online.

The equation that represents the number of tickets that Josiah can buy with $45.50

$3 + $8.50 × x = $45.50

3 + 8.50x = 45.50

Solving further for x

3 + 8.50x = 45.50

8.50x = 45.50 - 3

8.50x = 42.50

x = 42.50/8.50

x = 5

Hence, the number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

3 0

2 years ago

Your friend evaluates ( 10-k ) divided by 5 . K stands for 5 and the friend gets 9 as the answer . Explain the error

Oliga [24]

Answer:

(10 - k) ÷ 5 = 9

(10 - 5) ÷ 5 = 9

5 ÷ 5 = 9

1 = 9

1 does not equal 9

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8 0

2 years ago

How many lines can be constructed perpendicular to AC that pass through point D?

Vladimir [108]

Answer:

Step-by-step explanation:

This is the answer by definition.

5 0

1 year ago

Ali has 2 vegetables pizzas that she cuts into eighths.How many 1/8 size pics does she have

OlgaM077 [116]

16 assuming each pizza is cut into 8 pieces

7 0

2 years ago

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

2 years ago