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julsineya [31]
3 years ago
11

What is this equation simplified

^{3})2" alt=" ({x}^{3})2" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:

2x³

Step-by-step explanation:

2x³

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Question 3 of 10 A Assume EFG = JKL. If mLJ = 90°, mL K = 26°, and m< L = 64°, what is the measure of < E?
kumpel [21]

The measure of angle E will be 90 degrees as well.

Assume EFG = JKL.

If mLJ = 90°, mL K = 26°, and m< L = 64°,

<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given an image of two congruent triangles.

Since, EFG = JKL

therefore, the corresponding angles will be congruent.

m < J = 90° = m< E = 90

By congruence measure of angle, J will be equal to the measure of angle E.

Hence, The measure of angle E will be 90 degrees as well.

Learn more about congruent;

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Suppose two chemicals are reacted together. It takes 1000 kJ of energy to break the bonds of the reactants and 850 kJ of energy
dlinn [17]
B i think is is 150kj
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3 years ago
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What is the equivalent expression to 9+(5+3). <br><br> Help
Gelneren [198K]
9+(5+3) is going to be 17
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3 years ago
When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100
ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

and we can see that at the end of year 50, the future value is

\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

The sum  

\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

and the future value is then

\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

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3 years ago
Evaluate the expression x =5 for the given replacement
rewona [7]

Answer:

x=5 is not a problem.

Step-by-step explanation:

x would be 5 thats it.

7 0
3 years ago
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