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Makovka662 [10]
3 years ago
12

Jada has 126 blue marbles and 135 yellow marbles. She packages them in bags of 8 marbles each. She divides the total number of m

arbles by 8 and gets 32 R5. What is the correct interpretation of R5 for this situation? Jada can fill at most 32 bags with 5 marbles each. Jada has 5 bags left after filling 32 bags. Jada has 5 marbles left after filling 32 bags. Jada can fill 5 more bags after filling 32 bags.
Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

Jada has 5 marbles left after filling 32 bags.

Step-by-step explanation:

Jada has 126 blue marbles and 135 yellow marbles

Total Marbles=126+135=261

She divides by 8: 261/8=32\frac{5}{8} i.e. 32 Remainder 5 marbles.

The correct interpretation is Jada has 5 marbles left after filling 32 bags.

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Solving systems of equations using any method
andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer:  {x = 5 , y = 2

7 0
3 years ago
Convert 5 killogram into grams . here are the answer choices A.5,000 B.500 C.50 D. 5,500
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The answer to this question is 5000
7 0
2 years ago
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How do i express x^2-3x into the form of (x-m)^2+n. I will give brainliest to correct answer
mel-nik [20]

Step-by-step explanation:

let's simply do the multiplications and then compare with the original.

(x-m)² + n

right ?

or is it

{(x - m)}^{2 + n}

let's go for the first.

x² - 2mx + m² + n = x² - 3x

-2mx + m² + n = -3x

fun there we see two things :

-2m = -3

m = 3/2

and

m² + n = 0

(3/2)² = -n

9/4 = -n

n = -9/4

so our transformed expression looks like

(x - 3/2)² - 9/4

7 0
2 years ago
How many solutions does this system of equations have? Use either the substitution method or the elimination method. −2x + 4y =
Katen [24]
-2x+4y=4 Equation 1
x-2y=6 Equation 2
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Isolate x from equation 2.
x=2y+6 
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3 years ago
16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
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Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

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This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

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2 years ago
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