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Taya2010 [7]
3 years ago
14

The ages of the patients in a doctor's surgery are: 27, 13, 16, 20, 41 and 9. Find the mean of this set of data. Another patient

has just walked in and their age is 84. What is the mean of the patients now? How many patients are now over this mean age?
Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Answer:

The mean is 30 and there are 2 patients over this age.

Step-by-step explanation:

Add up 27+13+16+20+41+9+84=210

Then divide by the amount of numbers "7" so

210/7 is 30.

There are 2 patients over the age of 30.

Make sure that you are correct and do the problem twice.

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Suppose a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg,
lianna [129]

Answer:

(a) Probability that Y falls into the dangerous region is 0.0013.

(b) Probability that the mean Y-bar falls into the dangerous region is 0.00001.

Step-by-step explanation:

We are given that a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg, σ = 1 mg).

A dosage of 13 mg is considered dangerous.

Let Y = <u><em>dosage of the active ingredient </em></u>

The z-score probability distribution for normal distribution is given by;

                                 Z  =  \frac{ Y-\mu}{\sigma} } }  ~ N(0,1)

where, \mu = population mean = 10 mg

            \sigma = standard deviation = 1 mg

(a) Probability that Y falls into the dangerous region is given by = P(Y \geq 13 mg)

       P(Y \geq 13 mg) = P( \frac{ Y-\mu}{\sigma} } } \geq \frac{ 13-10}{1} } } ) = P(Z \geq 3) = 1 - P(Z < 3)  

                                                          = 1 - 0.9987 = <u>0.0013</u>

The above probability is calculated by looking at the value of x = 3 in the z table which has an area of 0.9987.

(b) We are given that a dosage of 13 mg is considered dangerous. And we sample 49 capsules at random.

Let \bar Y = sample mean dosage

The z-score probability distribution for sample mean is given by;

                                 Z  =  \frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }  ~ N(0,1)

where, \mu = population mean = 10 mg

            \sigma = standard deviation = 1 mg

            n = sample of capsules = 49

So, Probability that the mean Y-bar falls into the dangerous region is given by = P(\bar Y \geq 13 mg)

          P(Y \geq 13 mg) = P( \frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } } \geq \frac{13-10}{\frac{1}{\sqrt{49} } } } } ) = P(Z \geq 21) = 1 - P(Z < 21)  

                                                             = <u>0.00001</u>

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If angle 2 measures 155 degrees in the image below and what is the measurement of angle 1
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the diagram shown below. In that figure, we know that:

\angle 1=? \\ \\ \angle 2=155^{\circ}

The figure shows that these two angles are supplementary, so they add up to 180 degrees. Therefore:

\angle 1+\angle 2=180^{\circ} \\ \\ Substituting \ \angle 2=155^{\circ}: \\ \\ \angle 1+155^{\circ}=180^{\circ} \\ \\ \\ Isolating \ \angle 1: \\ \\ \angle 1=180^{\circ}-155^{\circ} \\ \\ \boxed{\angle 1=25^{\circ}}

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