The ages of the patients in a doctor's surgery are: 27, 13, 16, 20, 41 and 9. Find the mean of this set of data. Another patient
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So the easiest method to find the vertex (the minimum in this case) to do this is to find the axis of symmetry, then plug it into the function.
Firstly, the equation to find the axis of symmetry is , with b = x coefficient and a = x^2 coefficient. The equation equation can be solved as such:
Since the vertex falls on the axis of symmetry, we know that the x-coordinate of the vertex is -2.5. Now to solve for the y-coordinate, plug in x with -2.5 and solve as such:
Now putting it all together, our minimum value (vertex) is (-2.5,-12.25).
Six different sized rectangles that have an area of 64 square units:
1) 64 units x 1 unit
2) 32 units x 2 units
3) 16 units x 4 units
4) 40 units x 1.4 units
5) 20 units x 3.2 unit
6) 10 units x 6.4 units
For given question,
Let l be the length of the rectangle and w be the width of the rectangle.
We know that, the area of a rectangle is equal to
A = l × w
Here, A = 64 square units
So, we get an equation
l × w = 64 ...............................(1)
let's assume different values of l to get the different values of w.
Case 1) For l = 64 units
substitute in the equation 1
⇒ 64 × w = 64
⇒ w = 64/64
⇒ w = 1 units
The dimensions of the rectangle are 64 units x 1 unit
See the draw in the attached figure 1
Case 2) For l = 32 units
substitute in the equation 1
⇒ 32 × w = 64
⇒ w = 64/32
⇒ w = 2 units
The dimensions of the rectangle are 32 units x 2 unit
See the draw in the attached figure 2
Case 3) For l = 16 units
substitute in the equation 1
⇒ 16 × w = 64
⇒ w = 64/16
⇒ w = 4 units
The dimensions of the rectangle are 16 units x 4 unit
See the draw in the attached figure 3
Case 4) For l = 40 units
substitute in the equation 1
⇒ 40 × w = 64
⇒ w = 64/40
⇒ w = 1.4 units
The dimensions of the rectangle are 40 units x 1.4 unit
See the draw in the attached figure 4
Case 5) For l = 20 units
substitute in the equation 1
⇒ 20 × w = 64
⇒ w = 64/20
⇒ w = 3.2 units
The dimensions of the rectangle are 20 units x 3.2 unit
See the draw in the attached figure 5
Case 6) For l = 10 units
substitute in the equation 1
⇒ 10 × w = 64
⇒ w = 64/10
⇒ w = 6.4 units
The dimensions of the rectangle are 10 units x 6.4 unit
Learn more about the rectangle here:
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