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3 years ago

Answer this for 15 POINTS and BRAINLIEST

Mathematics

1 answer:

ziro4ka [17]3 years ago

6 0

Answer:

6/15=y

Step-by-step explanation:

cuz

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Donny is 11 and his dad is 43 now. How old was Donny when his dad was 5x older than donny then? PLS SHOW STEP BY STEP

FrozenT [24]

Donnie was 32 because when you subtract 43 from 11 30 equals to 32

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2 years ago

¿Cuantos triángulos hay?

nalin [4]

Answer:

Yo veo 16. tal vez sea mas...

Step-by-step explanation:

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3 years ago

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What is 2Log5(5x^3)+1/3log5(x^2+6 written as a single logarithm?

AveGali [126]

An important rule of logs is a*log b = log b^a.

Thus, 2 (log to the base 5 of )(5x^3) = (log to the base 5 of ) (5x^3)^2, or

(log to the base 5 of ) (25x^6).

Next, (1/3) (log to the base 5 of ) (x^2+6) = (log to the base 5 of ) (x^2+6)^(1/3).

Here, the addition in the middle of the given expression indicates multiplication:

2Log5(5x^3)+1/3log5(x^2+6) = (log to the base 5 of ) { (5x^3)^2 * (x^2+6)^(1/3) }.

Here we've expressed the given log quantity as a single log.

5 0

3 years ago

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PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

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Solve for x. 2/3(x - 7) = -2

son4ous [18]

2/3x -14/3 = -2 -foiled

2/3x = -6/3 +14/3 -common denominator

2/3x = 8/3

x = 8/3 * 3/2

x = 24/6

x= 4

4 0

3 years ago

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