B.
He has used the highest recommended percentages to calculate the amounts for the three categories.
Let's prove each one:
A) y=x-3
x=0→y=0-3→y=-3=-3 ok
x=2→y=2-3→y=-1 different to 5 No
B) y=x+3
x=0→y=0+3→y=3 different to -3 No
C) y=4x-3
x=0→y=4(0)-3=0-3→y=-3=-3 ok
x=2→y=4(2)-3=8-3→y=5=5 ok
x=3→y=4(3)-3=12-3→y=9=9 ok
x=4→y=4(4)-3=16-3→y=13=13 ok
D) y=4x+3
x=0→y=4(0)+3=0+3→y=3 different to -3 No
Answer: Option C) y=4x-3
If x=students, the equation would be x=12 (x is less than of equal to twelve). I don’t know what you mean by constraints; perhaps if you explain more, I could help?
The answer above is correct
A true equation from these numbers can be:
82 ÷ 2 = 41 ÷ 2 = 20.5
Hope this helps!
