First, convert 1 kg to g.
1 kg = 1000 g
So 1000 g = 1.28
Set up a proportion:
1000/1.28 = 250/x
Cross multiply:
1000x = 320
Divide 1000 to both sides:
x = 0.32
So 250g costs £0.32
Answer:
They buy 6 hotdogs and 5 popcorn
Step-by-step explanation:
Assume that they buy x hotdogs and y popcorn
∵ They buy a total of 11 hotdogs and popcorn
∵ The number of hotdogs is x and the number of popcorn is y
∴ x + y = 11 ⇒ (1)
∵ Hot dogs cost $2.50 each
∵ Popcorn costs $1.00 each
∵ They spend $20 on hot dogs and popcorn
→ Multiply x by 2.5 and y by 1, add the products and equate the sum by 20
∴ 2.5(x) + 1(y) = 20
∴ 2.5x + y = 20 ⇒ (2)
Now we have a system of equations to solve it
→ Subtract equation (1) from equation (2)
∵ (2.5x - x) + (y - y) = (20 - 11)
∴ 1.5x + 0 = 9
∴ 1.5x = 9
→ Divide both sides by 1.5 to find x
∴ x = 6
→ Substitute the value of x in equation (1) to find y
∵ 6 + y = 11
→ Subtract 6 from both sides
∴ 6 - 6 + y = 11 - 6
∴ y = 5
∴ They buy 6 hotdogs and 5 popcorn
The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>
The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.
i.e.
By factorization, we have:
Now, to get exactly 30 divisor.
- (p+2)² requires to give us 15 factors.
Therefore, we can have an equation p + 2 = p₁ × p₂²
where:
- p₁ and p₂ relate to different values of odd prime numbers.
So, for the least values of p + 2, Let us assume that:
p + 2 = 5 × 3²
p + 2 = 5 × 9
p + 2 = 45
p = 45 - 2
p = 43
Therefore, we can conclude that the smallest prime number p such that
p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
Learn more about prime numbers here:
brainly.com/question/145452
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Answer: He can raise up to 40 goats and 100 llamas.
Step-by-step explanation:
Hi, to answer this question we have to write system of equations with the information given:
The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)
4x +10y ≤ 800 (acres)
The amount of veterinary care (in $) each goat needs (110) multiplied by the number of goats (x); plus The amount of veterinary care each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)
110x +88y ≤ 14,520 (cost)
Multiplying the first equation by 27.5, and subtracting the second equation to the first one:
110x + 275y ≤22,000
-
110x +88y ≤ 14,520
____________
187y ≤ 7480
y ≤ 7480/187
y ≤ 40
Replacing y in the first equation
4x +10(40) ≤ 800
4x +400 ≤ 800
4x ≤ 800-400
4x ≤ 400
x ≤ 400/4
x ≤ 100
It would be a 50/50 chance that all of them would be girls
