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3 years ago

What is (2+2+3+10)x(8+9+-9+7)

Mathematics

2 answers:

qwelly [4]3 years ago

6 0

Answer:

255

Step-by-step explanation:

(2+2+3+10) × (8+9+-9+7)

First, remove the brackets:

2 + 2 + 3 + 10 × 8 + 9 + -9 + 7

Now calculate like so:

2 + 2 + 3 + 10 = 17

8 + 9 + -9 + 7 = 15

(17) × (15) = 17 × 15 = 255

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Norma-Jean [14]3 years ago

3 0

Answer:

Your answer for this question is 255.

Step-by-step explanation:

To solve this problem, we must remember how to use PEMDAS. This tells us that we must simplify what is in parentheses first, exponents next, then multiplication and division, and finally addition and subtraction. In this case, this means that we must first perform the operations inside of the parentheses before the multiplication of the two groups of parentheses.

If we simplify within both groups of parentheses, we get:

(2+2+3+10) * (8+9+-9+7)

= (17) * (15)

We get the above simplification by performing the addition of all of the constants in the first group of parentheses and performing the addition and subtraction in the second group (notice that the +9 and -9 cancel each other out).

Now, we must simply multiply together our final two values to obtain our final answer.

17 * 15 = 255

Therefore, your answer is 255.

Hope this helps!

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Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).

lys-0071 [83]

Answer:

$(x+1)^2 + (y- 3.5)^2 =64$

Step-by-step explanation:

We are given that endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : $x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

Substitute the values in formula

$x=\frac{7-9}{2} , y=\frac{2+5}{2}$

$x=-1 , y=3.5$

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

$d=\sqrt{(-9-7)^2+(5-2)^2}$

$d=\sqrt{265}$

Length of radius = r = $\frac{Diameter}{2}=\frac{\sqrt{256}}{2}$

Standard form of the equation of the circle : $(x -h)^2 + (y- k)^2 = r^2$

(h,k )=(-1,3.5)

$r=\frac{\sqrt{256}}{2}$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =64$

Hence the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is $(x+1)^2 + (y- 3.5)^2 =64$

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4 years ago

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3 years ago

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Answer:

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