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Effectus [21]
3 years ago
9

Plz help/ Trigonometric models and sine functions: plz show how you got and the GRAPH! Thx to anyone that can help

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

y=-2\sin(2x)-2 - The graph is attached below.

Step-by-step explanation:

Given : A sine function has the following key features:

Period = π , Amplitude = 2,  Midline: y = -2 , y-intercept: (0,-2)

The function is a reflection of its parent function over the x-axis.

To plot the graph :

Solution :

General form of sin function is y=A sin(Bx)+C

Where A is the amplitude

B=\frac{2\pi}{\text{Period}}

C is the midline    

Substitute the given key features  

A=2 , C=-2  

B=\frac{2\pi}{\pi}=2

The sin function is  y=2\sin(2x)-2

The function is a reflection of its parent function over the x-axis.

i.e, The coordinate became (x,y)→(x,-y)

The sin function is y=-2\sin(2x)-2

Now, We plot the graph of the sin function.

The graph is attached below.  

First point is midline i.e, (0,-2)

Minimum point is (\frac{\pi}{4},-4)

Vaselesa [24]3 years ago
5 0

Answer:

Step-by-step explanation:

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solniwko [45]

Answer:

20x + 42y

Step-by-step explanation:

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4 years ago
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Is (2, 3) a solution to this system of equations?<br> 2x + 5y = 19<br> X + 16y = 5<br> yes<br> no
chubhunter [2.5K]

Answer:

No

Step-by-step explanation:

To check if (2,3) is a solution to the system of equations, we simply have to plug the coordinate points into the two equations and see if it is valid.

2*2+5*3=\\4+15=\\19\\\\19=19

(2,3) belongs in the first equation.

2+16*3=\\2+48=\\50\\\\50\neq 5

(2,3) does not belong in the second equation.

<u>Therefore, (2,3) is not a solution to this system of equations.</u>

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<em>I hope this helps! Let me know if you have any questions :)</em>

3 0
3 years ago
A line passes through the points (3, −1) and (−5, 3) . What is the point-slope form of the line
aleksandrvk [35]
Hello here is a solution:
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let A(3;-1)   B(-5;3)
a= ((3)-(-1))/(-5)-(3))
a= 4/-8
a=-1/2
y=(-1/2) x+b
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8 0
3 years ago
What's -2x - 10 = 30
jeka57 [31]

Answer:

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4 0
3 years ago
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What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?
Vlad [161]

Answer:

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Step-by-step explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

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Similarly, change in x co-ordinates is given by

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Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

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∆y=65-80=-15

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Negative StartFraction 15 Over 2 EndFraction

4 0
3 years ago
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