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cupoosta [38]
3 years ago
6

Calculate the total mass of water in kg on Earth's surface from the following data: total planetary surface area: 510,066,000 km

2, land area of planet: 148,647,000 km2 , assume the average depth of water is:100.0km and the density of water is 1.00g/mL
(using dimensional analysis)
Geography
1 answer:
irinina [24]3 years ago
4 0

Answer:

The total mass of water in on Earth's surface is 3.61419\times 10^{22} kg.

Explanation:

Total planetary surface area = T = 510,066,000 km^2

Total land area of planet = L = 148,647,000 km^2

Total water area of planet = W

T = L + W

510,066,000 km^2=148,647,000 km^2-W

W=510,066,000 km^2-148,647,000 km^2=361,419,000 km^2

Volume = Area × Depth

Volume of water on earth = V

V= 361,419,000 km^2\times 100 km^=36,141,900,000 km^3

km^3=10^{12} L

V=36,141,900,000 km^3=36,141,900,000 \times 10^{12} L

Total mass of total water on the earth = M

Density of the water,D = 1 g/mL = 0.001 kg/0.001 L=1 kg/L

1 g - 0.001 kg

1 mL = 0.001 L

D=\frac{M}{V}

M=D\times V

M =1 kg/L\times 36,141,900,000 \times 10^{12} L=3.61419\times 10^{22} kg

The total mass of water in on Earth's surface is 3.61419\times 10^{22} kg.

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