Question

Calculate the total mass of water in kg on Earth's surface from the following data: total planetary surface area: 510,066,000 km2, land area of planet: 148,647,000 km2 , assume the average depth of water is:100.0km and the density of water is 1.00g/mL
(using dimensional analysis)

Answer 1

Answer:

The total mass of water in on Earth's surface is $3.61419\times 10^{22} kg$.

Explanation:

Total planetary surface area = T = $510,066,000 km^2$

Total land area of planet = L = $148,647,000 km^2$

Total water area of planet = W

T = L + W

$510,066,000 km^2=148,647,000 km^2-W$

$W=510,066,000 km^2-148,647,000 km^2=361,419,000 km^2$

Volume = Area × Depth

Volume of water on earth = V

V= $361,419,000 km^2\times 100 km^=36,141,900,000 km^3$

$km^3=10^{12} L$

$V=36,141,900,000 km^3=36,141,900,000 \times 10^{12} L$

Total mass of total water on the earth = M

Density of the water,D = 1 g/mL = 0.001 kg/0.001 L=1 kg/L

1 g - 0.001 kg

1 mL = 0.001 L

$D=\frac{M}{V}$

$M=D\times V$

$M =1 kg/L\times 36,141,900,000 \times 10^{12} L=3.61419\times 10^{22} kg$

The total mass of water in on Earth's surface is $3.61419\times 10^{22} kg$.