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3 years ago

Math lottssssss offf points

Mathematics

1 answer:

yan [13]3 years ago

5 0

Constant of Proportionality = d/t = 90/2 = 45 mph

In short, Constant of Proportionality would be: 45 miles per hour.

Here, d/t = 45
d = 45t

In short, Your Equation would be: d= 45t

Hope this helps!

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Help me with this I don’t really understand it

KIM [24]

Answer:

Could you please help me with the two most recent questions of mine on my page? I will give u brainliest and 20 points! :))) X

Step-by-step explanation:

6 0

3 years ago

How do you solve the literal equation <br><br> W > Y + H for H?<br> P

monitta

Subtract Y from both sides

H < W - Y

5 0

3 years ago

Help me find the volume of the composite figure

Butoxors [25]

Answer:

$V = 97.911in^3$

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

$V_1 = l^3$

Where

l = side length = 5.1

$V_1 = 5.1^3$

$V_1 = 132.651$

Next, calculate the volume of the cone using:

$V_2 = \frac{\pi r^2h}{3}$

Where

h = 5.1

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 5.1$

$r = 2.55$

So, we have:

$V_2 = \frac{\pi r^2h}{3}$

$V_2 = \frac{\pi * 2.55^2 * 5.1}{3}$

$V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}$

$V_2 = \frac{729.5805}{21}$

$V_2 = 34.74$

The volume of the figure is:

$V=V_1 - V_2$

$V_1 = 132.651$

$V = 132.651 - 34.74$

$V = 97.911in^3$

8 0

2 years ago

Write a compound inequality to represent all of the numbers between -4 and 6.

OlgaM077 [116]

-4<x<6
should be the correct answer because x is larger than -4 but 6 is larger than x.
you could also write it
-4<x AND x<6

6 0

3 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

3 years ago