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Eduardwww [97]
3 years ago
12

1. What are the term(s), coefficient(s), and

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

Step-by-step explanation:

6c + 5

term : 6c and 5....coefficient : 6......constant : 5

a coefficient is the number multiplied by the variable (the letter)....a constant is just a number with no variables (letters)

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Can someone help me plz
olya-2409 [2.1K]
9 cuz 4 times 1/2 is 2 and 2+7=9
3 0
3 years ago
The point K lies on the segment JL.
vlabodo [156]

Answer:

  • ( -9, 5)

Step-by-step explanation:

We can observe that x coordinate increases on line segment JL from J and y coordinate decreases.

<u>The difference in x:</u>

  • -18 - 3 = -21

<u>The difference in y:</u>

  • 17 - (-11) = 28

<u>Point K is at 3/7 distance from J, so it's coordinates will be:</u>

  • -18 -(-21*3/7) = -18 + 9 = -9
  • 17 - (28*3/7) = 12- 7 = 5

So K = ( -9, 5)

6 0
4 years ago
A population consists of 500 elements. We want to draw a simple random sample of 50 elements from this population. On the first
serious [3.7K]

Answer: correct option is A

0.100

Step-by-step explanation:

Given that

population = 500 elements.

To draw a simple random sample of 50 elements from this population. On the first selection

The probability = 50/500 = 0.1

The probability of an element being selected is 0.100

3 0
3 years ago
You purchase a $30, nonrefundable ticket to a play at a local theater. Ten minutes into the show you realize that it is not a ve
Luda [366]

Answer:

you should go home and read a book

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B60%7D%20%2F%5Csqrt%7B5%7D%20%28in%20radical%20form%29" id="TexFormula1" title="\sqrt
FinnZ [79.3K]

2\sqrt{3}

------------------------

Steps:

1st write out equation

\frac{\sqrt{60}}{\sqrt{5}} \\

Second write the conjugant and multiply it.

\frac{\sqrt{60}}{\sqrt{5}} * \frac{\sqrt{5} }{\sqrt{5} }

After multiplying you should get,

\frac{10\sqrt{3}}{5}

now after simplifying you should get

2\sqrt{3}

3 0
3 years ago
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