The pythagorean theorem holds for every right triangle: given the legs 
and the hypothenuse 
, the triangle is right if and only if
So, you have to check:
So the first triangle can't be a right triangle.
So the second triangle is a right triangle.
The third triangle can't be right, because it has the same legs but a different hypothenuse
Finally, we have
So the last triangle can't be a right triangle.
Answer:
(A) put the 7 in front of the log
log 6 (6)^7 = x
7 * log 6 (6) = x
7 * 1 = x
x = 7
Use combine like terms the answer is 7r^2-r-1
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
THE ANSWER IS D whoops lol sorry i was in an argument lol
