Question

28÷7-4^0+(-2)^3 How do I solve this? Thank you

Answer 1

To start off you would need to use the order of PEMDAS

Parenthesis
Exponents
Multiply
Divide
Add
Subtract

So first would be the exponents of -4^0 which would equal -1 because anything to the power of 0 is 1. Then (-2)^3 would just be (-2)x(-2)x(-2)= -8. Which gives 28/7-1+(-8)

After that it would be the division of 28 and 7. 4-1+(-8) is what you end up with and then then last 2 are adding then subtracting, so first you'd get 4-9. Then the last step which gives you 4-9=(-5) So your answer would be (-5)