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maks197457 [2]
4 years ago
6

28÷7-4^0+(-2)^3 How do I solve this? Thank you

Mathematics
1 answer:
lyudmila [28]4 years ago
8 0
To start off you would need to use the order of PEMDAS

Parenthesis
Exponents
Multiply
Divide
Add
Subtract

So first would be the exponents of -4^0 which would equal -1 because anything to the power of 0 is 1. Then (-2)^3 would just be (-2)x(-2)x(-2)= -8. Which gives 28/7-1+(-8)

After that it would be the division of 28 and 7. 4-1+(-8) is what you end up with and then then last 2 are adding then subtracting, so first you'd get 4-9. Then the last step which gives you 4-9=(-5) So your answer would be (-5)
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Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
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Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

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Step-by-step explanation:

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maks197457 [2]
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Marianna [84]

Answer:

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Step-by-step explanation:

As

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We can determine the value of P(A∩B) Using the formula

P(AUB) = P(A) + P(B) - P(A∩B)

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Therefore, the value of P(AUB) = 0.72

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Answer:

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