Answer:
Option (3). 120° will be the answer.
Step-by-step explanation:
By using the theorem of secants intersecting externally,
Measure of angle formed by two secants, from a point outside the circle is half the difference of the measures of the intercepted arcs.
m∠C = 
36° = 
72° = 
°
= 72 + 48
= 120°
Therefore, Option (3) is the answer.
Answer:
They are similar
Step-by-step explanation:
If two triangles are similar, the ratio of their corresponding side lengths must be equal to each other.
This means that for ∆LQP and ∆LMN to be considered similar to each other, therefore:
LM/LQ = LN/LP
LM = 100
LQ = 12
LN = 75
LP = 9
LM/LQ = 100/12 = 25/3
LN/LP = 75/9 = 25/3
LM/LQ = LN/LP = 25/3, therefore ∆LQP and ∆LMN are similar to each other because the ratio of their corresponding side lengths are the same.
<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph
