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LenaWriter [7]
3 years ago
13

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p: n = 195,

x = 162; 95% confidence.a. 0.788 < p < 0.873.
b. 0.789 < p < 0.873.
c. 0.778 < p < 0.883.
d. 0.777 < p < 0.884.
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

c. 0.778 < p < 0.883.

Step-by-step explanation:

The formula for confidence interval for proportion =

p ± z score × √p(1 - p)/n

p = x/n

n = 195, x = 162

z score for 95% confidence Interval = 1.96

p = 162/195

p = 0.8307692308

p ≈ approximately equal to = 0.8308

0.8308 ± 1.96 × √0.8308 × (1 - 0.8308)/195

0.8308 ± 1.96 ×√0.8308 × 0.1692/195

0.8308 ± 1.96 × √0.0007208788

0.8308 ± 1.96 × 0.0268491862

0.8308 ± 0.052624405

Confidence Interval

= 0.8308 - 0.052624405

= 0.778175595

Approximately = 0.778

= 0.8308 + 0.052624405

= 0.883424405

Approximately = p

0.883

Therefore, the confidence interval for this proportion = (0.778, 0.883) or option c. 0.778 < p < 0.883

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Answer:

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={cos^2(A/2)}^2 -{sin^2(A/2)}^2

={cos^2(A/2) - sin^2(A/2)}{cos^2(A/2) +sin^2(A/2)}

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5 0
4 years ago
HELP ME PLEASE!
shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

<em>Find the area of black circle</em>

r=3/2=1.5\ units    

x=(3.14)(1.5)^{2} =7.065\ units^{2}

<em>Find the total area of the square target</em>

y=9^{2}=81\ units^{2}

Find the probability

P=\frac{7.065}{81}=0.0872

Convert to percentage

0.0872*100=8.72\%

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

<em>Find the area of the white portion</em>

The area is equal to the area of the square minus the area of the circle

x=81-7.065=73.935\ units^{2}

Find the probability

P=\frac{73.935}{81}=0.9128

Convert to percentage

0.9128*100=91.28\%

The probability is closer to 1, because is greater than 50%

4 0
3 years ago
7. Tyson obtained a loan from the bank at 7.5% simple interest for 2. 5 years. If the simple interest was
9966 [12]

Answer:

7.He borrowed $1853.33

8.She received $28990.936

Step-by-step explanation:

7.Let x be the amount borrowed by Tyson

Rate of interest = 7.5%

Time = 2.5 years

Simple Interest = 347.50

Formula : Si = \frac{P \times T \times R}{100}

Where SI = simple interest

P = Principal

T = Time

R = Rate of interest

Substitute the values in the formula :

347.50=\frac{x \times 2.5 \times 7.5}{100}\\\frac{347.50 \times 100}{2.5 \times 7.5}=x\\1853.33=x

Hence he borrowed $1853.33

8) Principal = 20000

Rate of interest = 9.5%

No. of compounds per year = 2

Time = 4 years

Formula : A=P(1+\frac{r}{n})z^{nt}

Where A= amount

r = Rate of interest

n = no. of compounds

t = time

Substitute the values in the formula :

So, A=20000(1+\frac{9.5}{200})^{2(4)}

A=28990.936

Hence she received $28990.936

8 0
3 years ago
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Answer:

5+

Step-by-step explanation:

8 0
3 years ago
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Jet001 [13]
B because when you calculate it it should be it
4 0
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