All categories

3 years ago

(20n^2+N^3+10n^2) /10N^2

1 answer:

3 0

Combine like terms:
n^3 + 20n^ + 10n^2
= n^3 + 30n^

Divide:
=n^3 + 30n^2/10n^2

Factor:
=n^2n + 30n^2
=n^(n + 30)
= 2^2(n + 30)/10n^2

Cancel the common factor n^2:
=n + 10/10

You might be interested in

A preimage is the the original figure in a transformation. A) True B) False

Kitty [74]

Your answer is True! :) Reason: preimage is the original figure in transformation and preimage is the original figure in transformation.

7 0

2 years ago

Read 2 more answers

Solve (2x-1/4)+(x/3)=2 Please provide a step by step with explanation

andrew11 [14]

Answer:

x = 27/10 or x = 2.7

Step-by-step explanation:

Step 1: Get rid of the denominator.

LCD of 4 & 3: 12

Multiply both sides by 12.

12 ( 2x - 1 / 4 ) + 12 ( x / 3 ) = 12 (2)

Reduce the numbers.

3 ( 2x - 1) + 4x = 24

Step 2: Distribute.

6x - 3 + 4x = 24

Step 3: Collect like terms.

6x + 4x = 24 + 3 ( - 3, the sign change when moved to the other side)

10x = 27

Step 4: Solve for x.

Multiply both sides by 10.

10x / 10 = 27 / 10 (the 10 cancels out)

x = 27 / 10 or x = 2.7

Answer: x = 27 / 10 or x = 2.7

7 0

2 years ago

What is one plus one

inna [77]

Answer:

Step-by-step explanation:

21 lol

7 0

2 years ago

Read 2 more answers

H(x)=1/8x^3-x^2 Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

6 0

3 years ago

Help please 1 3/5 x 2 1/3=

Crank

Answer:

= 56/ 15 and 3 11/15

Step-by-step explanation:

1 3/5 x 2 1/3

= 8/5 x 7/3

3 0

2 years ago