let's first off convert those mixed fractions to improper fractions, then get their difference.
![\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}~\hfill \stackrel{mixed}{2\frac{1}{10}}\implies \cfrac{2\cdot 10+1}{10}\implies \stackrel{improper}{\cfrac{21}{10}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{21}{10}-\cfrac{3}{2}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(1)21-(5)3}{10}}\implies \cfrac{21-15}{10}\implies \cfrac{6}{10}\implies \cfrac{3}{5}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B3%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%2010%2B1%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B21%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B21%7D%7B10%7D-%5Ccfrac%7B3%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%2010%7D%7D%7B%5Ccfrac%7B%281%2921-%285%293%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B21-15%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B6%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B5%7D)
now, the original amount, 3/2, if that is the 100%, what is 3/5 off of it in percentage?

Answer:
degrees.
Step-by-step explanation:
Line ABC is a straight line, and the angle on a straight line is always 180 degrees.
Since ABD + DBC = ABC, we know that 

Divide both sides by 9:

DBC is
degrees.
Your procedure is perfect, you're fine, however, bear in mind that, in a calculator when plugging in values for some functions, specially trigonometric ones, if you tell it cos(40), and the calculator is in Radian mode, it thinks you meant cosine of 40 radian units, if you give it cos(40) and it's in Degree mode, it thinks you meant 40°, and 40 radians is hugely different than 40°.
so, make sure your calculator is in Degree mode, as you'd have guessed, it isn't.
Answer:
The second bubble
Explanation
You need to make your exponents equal the other side so to do this;
Distribute the 3 in the exponent "3(x-2)"
Which is 3x-6
And since multiplying exponents adds them, you need a -6 to make the two equal.
So your exponent should equal -6 to make that statement true