3(x−5)/2=2(x+5)/3
Cross-multiply.
(3(x−5))/2=(2(x+5))/3
3(x−5)*(3)=2(x+5)*(2)
9x−45=4x+20
Subtract 4x from both sides.
9x−45−4x=4x+20−4x
5x−45=20
Add 45 to both sides.
5x−45+45=20+45
5x=65
Divide both sides by 5.
5x/5=65/5
x=13
A tad more than 29 years, but that depends on the number of times it is being compounded
Answer:
I did it on Desmos
Step-by-step explanation:
Either (5,0) or (0,1)
