Answer:
The sample size is 183.
Step-by-step explanation:
Given:
σ = $1050, ppulatin standard deviation
99% confidence interval
Accuracy = +/- $200
The accuracy is given by
z*(σ/√n)
where
z* = 2.576 for 99% confidence level (from tables)
n = sample size
Therefore
2.576(1050/√n) = 200
√n = (2.576*1050)/200 = 13.524
n = 182.9
<em>The sample size is 183</em>
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A] From the graph, there is strong correlation between the satisfaction score and salary, this is implied by the closeness of the points on the graph.
b] Given that Hilda use the function y=0.0005x +60 to model the relationship, the score for $65000 will be given as follows;
y=0.0005(65000)+60
y=92.5
The number 0.0005 shows the rate of change of job satisfaction with salary
Answer:
75 %
Step-by-step explanation:
To solve for the above question,
The percentage of pupils that submitted their project on time
= Number of pupils that submitted their project on time/Number of pupils × 100
Number of pupils that submitted their project on time = 30 pupils
Number of pupils = 40 pupils
= 30/40 × 100
= 75 %
The percent of the pupils that submitted their project on time is 75%
Answer:
B, C, and D
Step-by-step explanation:
Just some simple maths, look at it like railroad tracks and act it out as such, with lines a and b being parallel. Angle 6 is 75, Angle 1 is 105
