Identify the vertex and y-intercept of the graph of the function y=(x+2)^2-3

Millie works 8 hours on Saturday and earns £6.50 an hour. Her bus fare to work costs £2.75 and she also spends £4.25 on her lunc

Nimfa-mama [501]

The answer is 7.50 ......

6 0

3 years ago

Find the next 3 terms in the sequence 1, 1, 2, 3, 5, 8, . . .

Lynna [10]

Easy.
C
Characterstofilluptherequiredammount

4 0

3 years ago

Solve for the value of X. -4x + 3 = 35

Stella [2.4K]

Answer:

-8

Step-by-step explanation:

4 0

2 years ago

Based on historical data, your manager believes that 37% of the company's orders come from first-time customers. A random sample

fomenos

Answer:

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$