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Sloan [31]
3 years ago
11

X^2-8x+6 in vertex form

Mathematics
1 answer:
kompoz [17]3 years ago
4 0
x^2-8x+6=\\
x^2-8x+16-10=\\
(x-4)^2-10
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So for the rhombus to carry onto itself, it needs to start in one position and end up in that same position. In this case, (x,y) will need to end up on (x,y) after the reflections are done. Here what the options do:

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