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3 years ago

7 1 3 — + — + — 9 7 5

Mathematics

1 answer:

Ghella [55]3 years ago

6 0

What kind of equation is that? That don't even look like an equation.

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Look at the picture for the question please show work.

lukranit [14]

$A=\dfrac{1}{2}ah\\
a=25 \text{ mm}\\
h=14 \text{ mm}\\\\
A=\dfrac{1}{2}\cdot25\cdot14\\
A=175 \text{ mm}^2 \Rightarrow C$

6 0

4 years ago

When does it stop being partly cloudy and start being partly sunny?

evablogger [386]

Answer:

50/50

Step-by-step explanation:

50/50

At what point does it stop being partly cloudy and start being partly sunny outside? 50/50, as you'd expect. Partly cloudy - In a forecast, this means that less than half of the day will be cloudy. For a current condition, this means that less than half of the sky is covered by clouds.

5 0

3 years ago

Given: △KLM, LM=20 3

egoroff_w [7]

Split the triangle into a 30-60-90 triangle. Since you have LM from that triangle, you can figure out the other sides. Then, using the leg from that triangle, the one next to it is a 45-45-90 triangle, meaning it's isosceles.

KM = 30 + 10√3

KL = 10√6

(sorry i'm not too sure if my "reasons" for statement/reason is correct)

6 0

3 years ago

Read 2 more answers

UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of

11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

Let $\mu$ = population average time someone spends in the gym

SO, Null Hypothesis, $H_0$ : $\mu$ = 56 minutes {means that the average time someone spends in the gym is 56 minutes}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 56 minutes {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average time someone takes in the gym = 50 min

$\sigma$ = population standard deviation = 8 minutes

n = sample of gym goers = 32

So, test statistics = $\frac{50-56}{\frac{8}{\sqrt{32} } }$

= -4.243

Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0

3 years ago

Find the range of the following piecewise function. [27,3) (-22,3] (27,3] [-22,3)

Otrada [13]

Answer:

The answer is "(27,3]"

Step-by-step explanation:

Please find the complete question in the attached file.

$\to f(-5) = (-5)^2 + 2 = 25 +2 =27\\\\\to f(7)= 7-4 = 3\\\\answer \ is = ( 27, 3]\$

5 0

3 years ago

Read 2 more answers