Answer:converge at 
Step-by-step explanation:
Given
Improper Integral I is given as

integration of
is -
![I=\left [ -\frac{1}{x}\right ]^{\infty}_3](https://tex.z-dn.net/?f=I%3D%5Cleft%20%5B%20-%5Cfrac%7B1%7D%7Bx%7D%5Cright%20%5D%5E%7B%5Cinfty%7D_3)
substituting value
![I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B%5Cinfty%20%7D-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)
![I=-\left [ 0-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%200-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)

so the value of integral converges at 
Answer:
a) 
b) 
Step-by-step explanation:
a) Let the required polynomial be p(x).
We have the relation,
+ p(x) = 18
i.e. p(x) = 18 
i.e. p(x) = 
b) Let the required polynomial be q(x).
We have the relation,
+ q(x) = 0
i.e. q(x) = 0 
i.e. q(x) = 
Answer:
27, you need to simplify both sides of the equation to get x on one side.
Step-by-step explanation:
Answer:
678996543456789
Step-by-step explanation:
Answer:
138, 460 m²
Step-by-step explanation:
How To Find Volume of Pyramid With Slant Height? If 'x' is the base length, 's' is the slant height, and 'h' is the height of a regular pyramid, then they satisfy the equation (the Pythagoras theorem) (x/2)2 + h2 = s2.