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3 years ago

Write the ordered pair that corresponds to point D and point H

Mathematics

1 answer:

kow [346]3 years ago

3 0

(-4,0) (3,-5) I don't know if they mean two ordered pairs so I'm pretty sure this is right

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You get a bagel for

Reika [66]

Answer:

You will get $1.96 in change.

Step-by-step explanation:

Add up the cost of the purchase

$1.95 for the bagel + $1.09 for the juice = $3.04

Subtract this from $5

$5 - $3.04 = $1.96

If this answer is correct, please make me Brainliest!

7 0

3 years ago

Maggie was thinking of a number. If she multiply the number by 3 ,subtracted by 8 ,added by 2 times the 5 original number . the

Fiesta28 [93]

I hope this helps you

number is ?

3.?-8+2.5.?=48

13.?=56

?=56/13

6 0

3 years ago

Pls help me with this question

bagirrra123 [75]

Answer:

i cant uderstand anything

Step-by-step explanation:

4 0

3 years ago

Find the following <br> (u•w)(2)=<br> (w•u)(2)=

Viefleur [7K]

Answer:

$(u \circ w)(2) = -34$

$(w \circ u) = -49$

Step-by-step explanation:

We are given these following functions:

$u(x) = 4x + 2$

$w(x) = -5x + 1$

The first step to solve this question is finding the composite functions. So

$(u \circ w)(x) = u(w(x)) = u(-5x+1) = 4(-5x + 1) + 2 = -20x + 6$

$(w \circ u)(x) = w(u(x)) = w(4x + 2) = -5(4x+2) + 1 = -20x - 9$

At x = 2

Now we replace x by 2 in each of the functions. So

$(u \circ w)(2) = -20(2) + 6 = -40 + 6 = -34$

$(w \circ u)(2) = -20(2) - 9 = -40 - 9 = -49$

5 0

3 years ago

Consider the following statement There are real numbers and such that Va+ V + b in the box below, as an ordered, comma that sati

Sever21 [200]

Answer:

a=0, b=16, of the pair (0,16)

Step-by-step explanation:

You want to prove the following: There are real numbers a and b such that $\sqrt{a+b}=\sqrt{a}+\sqrt{b}$

So, to prove this, it is enough to find a pair (a,b) of real numbers for which the equation holds true. There are infinite of such pairs, but one example is (0,16). Indeed:

$\sqrt{a+b}=\sqrt{0+16}=\sqrt{16}=4=0+4=\sqrt{0}+\sqrt{16}=\sqrt{a}+\sqrt{b}$

In fact, (0,m) or (n,0) ara valid pairs, for nonnegative numbers m,n. Even more is true; these are the only pairs which satisfy the equation.

3 0

4 years ago