Find the total area of the shaded region in the composite figure, round to the nearest tenth.

An indoor water park has two giant buckets that slowly fill with 1000 gallons of water before dumping it on the people below. On

Art [367]

Answer:

The next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

Step-by-step explanation:

From the question, one bucket dumps water every 18 minutes, say bucket A;

and the other bucket dumps water every 16 minutes, say bucket B.

Also, It is currently 2:45 P.M. and both buckets dumped water 15 minutes ago,

that is, both buckets dumped water at 2:30 P.M.

For bucket A, the next times it will dump water will be:

2:48 P.M, 3:06 P.M, 3:24 P.M, 3:42 P.M, 4:00 P.M, 4:18 P.M, 4:36 P.M, 4:54 P.M, 5:12 P.M, 5:30 P.M, 5:48 P.M, 6:06 P.M, 6:24 P.M, 6:42 P.M, 7:00 P.M, 7:18 P.M, 7:36 P.M, 7:54 P.M, 8:12 P.M, 8:30 P.M etc.

For bucket B, the next times it will dump water will be:

2:46 P.M, 3:02 P.M, 3:18 P.M, 3:34 P.M, 3:50 P.M, 4:06 P.M, 4:22 P.M, 4:38 P.M, 4:54 P.M, 5:10 P.M, 5:26 P.M, 5:42 P.M, 5:58 P.M, 6:14 P.M, 6:30 P.M, 6:46 P.M, 7:02 P.M, 7:18 P.M, 7:34 P.M, 7:50 P.M etc.

From above, we observe that the next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

Hence, the next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

6 0

3 years ago

In addition, what is the inverse

insens350 [35]

Answer:

it is

-3/7=3/7

brainliest s

if u want

5 0

2 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

3 years ago

There is an ice cream and candy shop next door that is the same size as your bakery. How many thirtieths of the space does it ta

SSSSS [86.1K]

Answer:

135,000 times

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.

<u>We need to know the size of your bakery store. </u>

As we can see, the entire shopping center is: 45000 square feet and your shop is 1/10 of that space

=> Your shop area is: 45000*1/10 = 4500 square feet

In the question, they want to know how many thirtieths of the space does it take up, so let say thirtieths in numerical is: 1/30

Hence, the number of thirtieths it takes:

$\frac{Area}{Thirtieths}$ = $\frac{4500}{\frac{1}{30} }$ = 135,000 times

Hope it will find you well.

8 0

3 years ago

Which data set is the farthest from a normal distribution?

Rudik [331]

Answer:

(C)0.9, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.3

Step-by-step explanation:

In (A), (B), (D) and (E) options, all have similar set of numbers and ranges between 2 to 10. Moreover these contains the whole numbers, so when we find mode, median and mean of these data sets, they will follow the same path.

But in (C), the data values involves decimals and are not the part of the other data values and it goes from 0.9-1.3, thus making them farthest from a normal distribution when mean, mode and median are calculated.

Thus, option (C) is correct.

5 0

3 years ago

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