Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Do you have a specific equation I can help you with. I can explain them better with a problem to look at?
2x+2=6
2x=4
x=2
Hope this helps :)
-1-1 or 2-4 or 3-5 or 6-8 or 7-9 or 8-10
F(x)=-3(x)+4
Therefore this implies that we must put the -4 where we see an X on the equation
F(-4)=-3(-4)+4
=16
