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Valentin [98]
3 years ago
12

Help! I’ll mark brainlest :(

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

I'm guessing its b, but I'm not too sure

Step-by-step explanation:

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Awarding BRAINLIEST! Please help!!
MariettaO [177]
The correct answer is -1/3.
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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
EleoNora [17]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

b) P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

c) P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

d) E(X) = 20*0.2= 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

P(X=4)

And using the probability mass function we got:

P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

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3 years ago
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Nataliya [291]
Use substitution and substitute y into the other equation. One of the equations already gives you y in terms of x, so use that and substitute it into the other equation. y = 3x - 4

Plug into the other equation: -3y = -9x + 12 
-3(3x-4) = -9x + 12
-9x + 12 = -9x + 12
This is an identity. So that means that any value of x makes this equation true. So B.
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3 years ago
3x-2y=6 thats The Problem I Need Help On
Roman55 [17]
Solve for Y?

Subtract -3x.
Then didvidd by -2 to get Y by itself.

Y= 3/2y -3

X-Intercept: (2,0)
Y-Intercept: (0,-3)

6 0
3 years ago
Disk requests come in to the disk driver for cylinders 10, 22, 20, 2, 40, 6, and 38, in that order. A seek takes 6 msec per cyli
m_a_m_a [10]

Answer:

a) 876 ms

b) 360 ms

c) 348 ms

Step-by-step explanation:

a) When using the  First-come, first serve order, the starts at the initial cylinder  and is served in the same order as it arrives.

For  First-come, first serve, the order is served from (20), 10, 22, 20, 2, 40, 6, and 38.

Seek time = 10 + 12 + 2+ 18 + 38 + 34 + 32 = 146 cylinder

The request uses 146 cylinders, therefore the seek time = 146 cylinder * 6 ms/cylinder = 876 ms

b) When using the Closest cylinder next the  request starts at the initial cylinder  and is served using the shortest movement from current position.

For Elevator algorithm, the order is served from (20), 20, 22, 10, 6, 2, 38, 40

Seek time = 0 + 2 + 12+ 4 + 4 + 36 + 2 = 60 cylinder

The request uses 146 cylinders, therefore the seek time = 60 cylinder * 6 ms/cylinder = 360 ms

c) When using the Elevator algorithm the  request starts at the initial cylinder and moves upwards, then reverses direction.

For  Closest cylinder next, the order is served from (20), 20, 22, 38, 40, 10, 6, 2

Seek time = 0 + 2 + 16+ 2 + 30 + 4 + 4 = 58 cylinder

The request uses 146 cylinders, therefore the seek time = 58 cylinder * 6 ms/cylinder = 348 msa) When using the  First-come, first serve order, the starts at the initial cylinder  and is served in the same order as it arrives.

For  First-come, first serve, the order is served from (20), 10, 22, 20, 2, 40, 6, and 38.

Seek time = 10 + 12 + 2+ 18 + 38 + 34 + 32 = 146 cylinder

The request uses 146 cylinders, therefore the seek time = 146 cylinder * 6 ms/cylinder = 876 ms

b) When using the Closest cylinder next the  request starts at the initial cylinder  and is served using the shortest movement from current position.

For Elevator algorithm, the order is served from (20), 20, 22, 10, 6, 2, 38, 40

Seek time = 0 + 2 + 12+ 4 + 4 + 36 + 2 = 60 cylinder

The request uses 146 cylinders, therefore the seek time = 60 cylinder * 6 ms/cylinder = 360 ms

c) When using the Elevator algorithm the  request starts at the initial cylinder and moves upwards, then reverses direction.

For  Closest cylinder next, the order is served from (20), 20, 22, 38, 40, 10, 6, 2

Seek time = 0 + 2 + 16+ 2 + 30 + 4 + 4 = 58 cylinder

The request uses 146 cylinders, therefore the seek time = 58 cylinder * 6 ms/cylinder = 348 ms

3 0
3 years ago
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