What are the lengths of the legs of a triangle in which one acute angle measures 19 degrees and the hypotenuse is 15 units long?
1 answer:
Sin (19°) = side a / 15
side a = 15 * sin (19°)
side a = 15 * 0.32557
side a = <span> <span> <span> 4.88355 </span> </span> </span>
side b^2 = 15^2 - 4.88355^2
side b^2 = 225 - <span> <span> <span> 23.8490606025 </span> </span> </span>
<span><span>side b^2 = 201.15</span>
side b = </span> <span> <span> <span> 14.18</span></span></span>
side a = 15 * sin (19°)
side a = 15 * 0.32557
side a = <span> <span> <span> 4.88355 </span> </span> </span>
side b^2 = 15^2 - 4.88355^2
side b^2 = 225 - <span> <span> <span> 23.8490606025 </span> </span> </span>
<span><span>side b^2 = 201.15</span>
side b = </span> <span> <span> <span> 14.18</span></span></span>
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