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KIM [24]
2 years ago
15

Find the sum of each series, if it exists91 + 85 + 79 + … + (­29)

Mathematics
1 answer:
Natali [406]2 years ago
5 0

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

91+85+79+...+(-29)

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

a_n=a+(n-1)d

where, a is first term and d is common difference.

-29=91+(n-1)(-6)

-29-91=(n-1)(-6)

\dfrac{-120}{-6}=(n-1)

20=(n-1)

n=20+1=21

Sum of AP is

Sum=\dfrac{n}{2}[\text{First term + Last term}]

Sum=\dfrac{21}{2}[91+(-29)]

Sum=\dfrac{21}{2}[62]

Sum=651

Therefore, the sum of given series is 651.

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3 years ago
Which expression is equivalent to 16x16x16
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Answer:

16^3

Step-by-step explanation:

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6 0
2 years ago
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What is the approximate value of k?
lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,

From the law of sines

sin(120)/k = sin(20)/2  =>

sin(120) =  k *  (  sin(20)/2) )                (multiply both sides by "k")

k = sin(120)/  (   sin(20)/2)                    (divide both sides by sin(20)/2)

k =  (0.866) /  ( 0.171) =  5.06


Regards,  

MrB

 P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


6 0
2 years ago
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Answer:

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Step-by-step explanation:

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