Answer: 4%-16000 and 9.5%-30000
Why:
1) x+y=46000
x=46000-y
2) 4%x+9,5%y=3490;
4x + 9.5y=349000; so 4*(46000-y)+9.5y=349000;
5.5y=165000
y=30000
x=46000-30000=16000
Answer:
30% is the correct answer.
Step-by-step explanation:
Total number of boys = 2
Total number of girls = 3
Total number of students = 5
To find:
Probability that the pianist will be a boy and the alternate will be a girl?
Solution:
Here we have to make 2 choices.
1st choice has to be boy (pianist) and 2nd choice has to be girl (alternate).

Formula for probability of an event E is given as:

For
, number of favorable cases are 2 (total number of boys).
Total number of cases = Total number of students i.e. 5
So,
is:

For
, number of favorable cases are 3 (total number of girls).
Now, one boy is already chosen as pianist so Total number of cases = Total number of students left i.e. (5 - 1) = 4

So, the required probability is:

Answer: Thought I’d return the favor and help u with this question! But anyways, the axis of symmetry is at x = -3.
Explanatio: This can be found by looking at the basic form of vertex form:
y = (x - h)^2 + k
In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = -4. This means the vertex is at (-3, -4).
It is a fact that the axis of symmetry is a vertical line of x = (vertex value of x). So we can determine that the axis of symmetry is at x = -3
i hope this helps u
Answer:
Step-by-step explanation:
When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to
are ...
- ∆ = bd -ea
- x = (bf -ec)/∆
- y = (cd -fa)/∆
Using that rule here, we find ...
∆ = 5·3 -6·2 = 3
a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8
s = (41·3 -54·2)/3 = 41 -18·2 = 5
This math can be performed in your head, which is the intent of formulating the rule in this way.
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Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.
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<em>Comment on the question</em>
We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.